3.722 \(\int \frac {(d x)^{3/2}}{(a^2+2 a b x^2+b^2 x^4)^3} \, dx\)

Optimal. Leaf size=389 \[ -\frac {231 d^{3/2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}-\frac {231 d^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5} \]

[Out]

-231/16384*d^(3/2)*arctan(1-b^(1/4)*2^(1/2)*(d*x)^(1/2)/a^(1/4)/d^(1/2))/a^(19/4)/b^(5/4)*2^(1/2)+231/16384*d^
(3/2)*arctan(1+b^(1/4)*2^(1/2)*(d*x)^(1/2)/a^(1/4)/d^(1/2))/a^(19/4)/b^(5/4)*2^(1/2)-231/32768*d^(3/2)*ln(a^(1
/2)*d^(1/2)+x*b^(1/2)*d^(1/2)-a^(1/4)*b^(1/4)*2^(1/2)*(d*x)^(1/2))/a^(19/4)/b^(5/4)*2^(1/2)+231/32768*d^(3/2)*
ln(a^(1/2)*d^(1/2)+x*b^(1/2)*d^(1/2)+a^(1/4)*b^(1/4)*2^(1/2)*(d*x)^(1/2))/a^(19/4)/b^(5/4)*2^(1/2)-1/10*d*(d*x
)^(1/2)/b/(b*x^2+a)^5+1/160*d*(d*x)^(1/2)/a/b/(b*x^2+a)^4+1/128*d*(d*x)^(1/2)/a^2/b/(b*x^2+a)^3+11/1024*d*(d*x
)^(1/2)/a^3/b/(b*x^2+a)^2+77/4096*d*(d*x)^(1/2)/a^4/b/(b*x^2+a)

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Rubi [A]  time = 0.50, antiderivative size = 389, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 10, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {28, 288, 290, 329, 211, 1165, 628, 1162, 617, 204} \[ -\frac {231 d^{3/2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}-\frac {231 d^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5} \]

Antiderivative was successfully verified.

[In]

Int[(d*x)^(3/2)/(a^2 + 2*a*b*x^2 + b^2*x^4)^3,x]

[Out]

-(d*Sqrt[d*x])/(10*b*(a + b*x^2)^5) + (d*Sqrt[d*x])/(160*a*b*(a + b*x^2)^4) + (d*Sqrt[d*x])/(128*a^2*b*(a + b*
x^2)^3) + (11*d*Sqrt[d*x])/(1024*a^3*b*(a + b*x^2)^2) + (77*d*Sqrt[d*x])/(4096*a^4*b*(a + b*x^2)) - (231*d^(3/
2)*ArcTan[1 - (Sqrt[2]*b^(1/4)*Sqrt[d*x])/(a^(1/4)*Sqrt[d])])/(8192*Sqrt[2]*a^(19/4)*b^(5/4)) + (231*d^(3/2)*A
rcTan[1 + (Sqrt[2]*b^(1/4)*Sqrt[d*x])/(a^(1/4)*Sqrt[d])])/(8192*Sqrt[2]*a^(19/4)*b^(5/4)) - (231*d^(3/2)*Log[S
qrt[a]*Sqrt[d] + Sqrt[b]*Sqrt[d]*x - Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d*x]])/(16384*Sqrt[2]*a^(19/4)*b^(5/4)) + (2
31*d^(3/2)*Log[Sqrt[a]*Sqrt[d] + Sqrt[b]*Sqrt[d]*x + Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d*x]])/(16384*Sqrt[2]*a^(19/
4)*b^(5/4))

Rule 28

Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Dist[1/c^p, Int[u*(b/2 + c*x^n)^(2*
p), x], x] /; FreeQ[{a, b, c, n}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 211

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Di
st[1/(2*r), Int[(r - s*x^2)/(a + b*x^4), x], x] + Dist[1/(2*r), Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[
{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b
]]))

Rule 288

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^
n)^(p + 1))/(b*n*(p + 1)), x] - Dist[(c^n*(m - n + 1))/(b*n*(p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] &&  !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]

Rule 290

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(
a*c*n*(p + 1)), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; FreeQ[
{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {(d x)^{3/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^3} \, dx &=b^6 \int \frac {(d x)^{3/2}}{\left (a b+b^2 x^2\right )^6} \, dx\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {1}{20} \left (b^4 d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^5} \, dx\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {\left (3 b^3 d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^4} \, dx}{64 a}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {\left (11 b^2 d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^3} \, dx}{256 a^2}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {\left (77 b d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^2} \, dx}{2048 a^3}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}+\frac {\left (231 d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )} \, dx}{8192 a^4}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}+\frac {(231 d) \operatorname {Subst}\left (\int \frac {1}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{4096 a^4}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}+\frac {231 \operatorname {Subst}\left (\int \frac {\sqrt {a} d-\sqrt {b} x^2}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{8192 a^{9/2}}+\frac {231 \operatorname {Subst}\left (\int \frac {\sqrt {a} d+\sqrt {b} x^2}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{8192 a^{9/2}}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}-\frac {\left (231 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {d x}\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}-\frac {\left (231 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {d x}\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}+\frac {\left (231 d^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {d x}\right )}{16384 a^{9/2} b^{3/2}}+\frac {\left (231 d^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {d x}\right )}{16384 a^{9/2} b^{3/2}}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}-\frac {231 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}+\frac {\left (231 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}-\frac {\left (231 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}\\ &=-\frac {d \sqrt {d x}}{10 b \left (a+b x^2\right )^5}+\frac {d \sqrt {d x}}{160 a b \left (a+b x^2\right )^4}+\frac {d \sqrt {d x}}{128 a^2 b \left (a+b x^2\right )^3}+\frac {11 d \sqrt {d x}}{1024 a^3 b \left (a+b x^2\right )^2}+\frac {77 d \sqrt {d x}}{4096 a^4 b \left (a+b x^2\right )}-\frac {231 d^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{8192 \sqrt {2} a^{19/4} b^{5/4}}-\frac {231 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}+\frac {231 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{16384 \sqrt {2} a^{19/4} b^{5/4}}\\ \end {align*}

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Mathematica [A]  time = 0.17, size = 298, normalized size = 0.77 \[ \frac {d \sqrt {d x} \left (-\frac {1155 \sqrt {2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{a^{19/4} \sqrt {x}}+\frac {1155 \sqrt {2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{a^{19/4} \sqrt {x}}-\frac {2310 \sqrt {2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{a^{19/4} \sqrt {x}}+\frac {2310 \sqrt {2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right )}{a^{19/4} \sqrt {x}}+\frac {3080 \sqrt [4]{b}}{a^4 \left (a+b x^2\right )}+\frac {1760 \sqrt [4]{b}}{a^3 \left (a+b x^2\right )^2}+\frac {1280 \sqrt [4]{b}}{a^2 \left (a+b x^2\right )^3}+\frac {1024 \sqrt [4]{b}}{a \left (a+b x^2\right )^4}-\frac {16384 \sqrt [4]{b}}{\left (a+b x^2\right )^5}\right )}{163840 b^{5/4}} \]

Antiderivative was successfully verified.

[In]

Integrate[(d*x)^(3/2)/(a^2 + 2*a*b*x^2 + b^2*x^4)^3,x]

[Out]

(d*Sqrt[d*x]*((-16384*b^(1/4))/(a + b*x^2)^5 + (1024*b^(1/4))/(a*(a + b*x^2)^4) + (1280*b^(1/4))/(a^2*(a + b*x
^2)^3) + (1760*b^(1/4))/(a^3*(a + b*x^2)^2) + (3080*b^(1/4))/(a^4*(a + b*x^2)) - (2310*Sqrt[2]*ArcTan[1 - (Sqr
t[2]*b^(1/4)*Sqrt[x])/a^(1/4)])/(a^(19/4)*Sqrt[x]) + (2310*Sqrt[2]*ArcTan[1 + (Sqrt[2]*b^(1/4)*Sqrt[x])/a^(1/4
)])/(a^(19/4)*Sqrt[x]) - (1155*Sqrt[2]*Log[Sqrt[a] - Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x] + Sqrt[b]*x])/(a^(19/4)*S
qrt[x]) + (1155*Sqrt[2]*Log[Sqrt[a] + Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x] + Sqrt[b]*x])/(a^(19/4)*Sqrt[x])))/(1638
40*b^(5/4))

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fricas [A]  time = 1.20, size = 485, normalized size = 1.25 \[ \frac {4620 \, {\left (a^{4} b^{6} x^{10} + 5 \, a^{5} b^{5} x^{8} + 10 \, a^{6} b^{4} x^{6} + 10 \, a^{7} b^{3} x^{4} + 5 \, a^{8} b^{2} x^{2} + a^{9} b\right )} \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {d x} a^{14} b^{4} d \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {3}{4}} - \sqrt {a^{10} b^{2} \sqrt {-\frac {d^{6}}{a^{19} b^{5}}} + d^{3} x} a^{14} b^{4} \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {3}{4}}}{d^{6}}\right ) + 1155 \, {\left (a^{4} b^{6} x^{10} + 5 \, a^{5} b^{5} x^{8} + 10 \, a^{6} b^{4} x^{6} + 10 \, a^{7} b^{3} x^{4} + 5 \, a^{8} b^{2} x^{2} + a^{9} b\right )} \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {1}{4}} \log \left (231 \, a^{5} b \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {1}{4}} + 231 \, \sqrt {d x} d\right ) - 1155 \, {\left (a^{4} b^{6} x^{10} + 5 \, a^{5} b^{5} x^{8} + 10 \, a^{6} b^{4} x^{6} + 10 \, a^{7} b^{3} x^{4} + 5 \, a^{8} b^{2} x^{2} + a^{9} b\right )} \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {1}{4}} \log \left (-231 \, a^{5} b \left (-\frac {d^{6}}{a^{19} b^{5}}\right )^{\frac {1}{4}} + 231 \, \sqrt {d x} d\right ) + 4 \, {\left (385 \, b^{4} d x^{8} + 1760 \, a b^{3} d x^{6} + 3130 \, a^{2} b^{2} d x^{4} + 2648 \, a^{3} b d x^{2} - 1155 \, a^{4} d\right )} \sqrt {d x}}{81920 \, {\left (a^{4} b^{6} x^{10} + 5 \, a^{5} b^{5} x^{8} + 10 \, a^{6} b^{4} x^{6} + 10 \, a^{7} b^{3} x^{4} + 5 \, a^{8} b^{2} x^{2} + a^{9} b\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^3,x, algorithm="fricas")

[Out]

1/81920*(4620*(a^4*b^6*x^10 + 5*a^5*b^5*x^8 + 10*a^6*b^4*x^6 + 10*a^7*b^3*x^4 + 5*a^8*b^2*x^2 + a^9*b)*(-d^6/(
a^19*b^5))^(1/4)*arctan(-(sqrt(d*x)*a^14*b^4*d*(-d^6/(a^19*b^5))^(3/4) - sqrt(a^10*b^2*sqrt(-d^6/(a^19*b^5)) +
d^3*x)*a^14*b^4*(-d^6/(a^19*b^5))^(3/4))/d^6) + 1155*(a^4*b^6*x^10 + 5*a^5*b^5*x^8 + 10*a^6*b^4*x^6 + 10*a^7*
b^3*x^4 + 5*a^8*b^2*x^2 + a^9*b)*(-d^6/(a^19*b^5))^(1/4)*log(231*a^5*b*(-d^6/(a^19*b^5))^(1/4) + 231*sqrt(d*x)
*d) - 1155*(a^4*b^6*x^10 + 5*a^5*b^5*x^8 + 10*a^6*b^4*x^6 + 10*a^7*b^3*x^4 + 5*a^8*b^2*x^2 + a^9*b)*(-d^6/(a^1
9*b^5))^(1/4)*log(-231*a^5*b*(-d^6/(a^19*b^5))^(1/4) + 231*sqrt(d*x)*d) + 4*(385*b^4*d*x^8 + 1760*a*b^3*d*x^6
+ 3130*a^2*b^2*d*x^4 + 2648*a^3*b*d*x^2 - 1155*a^4*d)*sqrt(d*x))/(a^4*b^6*x^10 + 5*a^5*b^5*x^8 + 10*a^6*b^4*x^
6 + 10*a^7*b^3*x^4 + 5*a^8*b^2*x^2 + a^9*b)

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giac [A]  time = 0.21, size = 340, normalized size = 0.87 \[ \frac {1}{163840} \, d {\left (\frac {2310 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{5} b^{2}} + \frac {2310 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{5} b^{2}} + \frac {1155 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x + \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{5} b^{2}} - \frac {1155 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x - \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{5} b^{2}} + \frac {8 \, {\left (385 \, \sqrt {d x} b^{4} d^{10} x^{8} + 1760 \, \sqrt {d x} a b^{3} d^{10} x^{6} + 3130 \, \sqrt {d x} a^{2} b^{2} d^{10} x^{4} + 2648 \, \sqrt {d x} a^{3} b d^{10} x^{2} - 1155 \, \sqrt {d x} a^{4} d^{10}\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{5} a^{4} b}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^3,x, algorithm="giac")

[Out]

1/163840*d*(2310*sqrt(2)*(a*b^3*d^2)^(1/4)*arctan(1/2*sqrt(2)*(sqrt(2)*(a*d^2/b)^(1/4) + 2*sqrt(d*x))/(a*d^2/b
)^(1/4))/(a^5*b^2) + 2310*sqrt(2)*(a*b^3*d^2)^(1/4)*arctan(-1/2*sqrt(2)*(sqrt(2)*(a*d^2/b)^(1/4) - 2*sqrt(d*x)
)/(a*d^2/b)^(1/4))/(a^5*b^2) + 1155*sqrt(2)*(a*b^3*d^2)^(1/4)*log(d*x + sqrt(2)*(a*d^2/b)^(1/4)*sqrt(d*x) + sq
rt(a*d^2/b))/(a^5*b^2) - 1155*sqrt(2)*(a*b^3*d^2)^(1/4)*log(d*x - sqrt(2)*(a*d^2/b)^(1/4)*sqrt(d*x) + sqrt(a*d
^2/b))/(a^5*b^2) + 8*(385*sqrt(d*x)*b^4*d^10*x^8 + 1760*sqrt(d*x)*a*b^3*d^10*x^6 + 3130*sqrt(d*x)*a^2*b^2*d^10
*x^4 + 2648*sqrt(d*x)*a^3*b*d^10*x^2 - 1155*sqrt(d*x)*a^4*d^10)/((b*d^2*x^2 + a*d^2)^5*a^4*b))

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maple [A]  time = 0.02, size = 335, normalized size = 0.86 \[ -\frac {231 \sqrt {d x}\, d^{11}}{4096 \left (b \,d^{2} x^{2}+d^{2} a \right )^{5} b}+\frac {331 \left (d x \right )^{\frac {5}{2}} d^{9}}{2560 \left (b \,d^{2} x^{2}+d^{2} a \right )^{5} a}+\frac {313 \left (d x \right )^{\frac {9}{2}} b \,d^{7}}{2048 \left (b \,d^{2} x^{2}+d^{2} a \right )^{5} a^{2}}+\frac {11 \left (d x \right )^{\frac {13}{2}} b^{2} d^{5}}{128 \left (b \,d^{2} x^{2}+d^{2} a \right )^{5} a^{3}}+\frac {77 \left (d x \right )^{\frac {17}{2}} b^{3} d^{3}}{4096 \left (b \,d^{2} x^{2}+d^{2} a \right )^{5} a^{4}}+\frac {231 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, d \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )}{16384 a^{5} b}+\frac {231 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, d \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )}{16384 a^{5} b}+\frac {231 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, d \ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )}{32768 a^{5} b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^3,x)

[Out]

-231/4096*d^11/(b*d^2*x^2+a*d^2)^5/b*(d*x)^(1/2)+331/2560*d^9/(b*d^2*x^2+a*d^2)^5/a*(d*x)^(5/2)+313/2048*d^7/(
b*d^2*x^2+a*d^2)^5/a^2*b*(d*x)^(9/2)+11/128*d^5/(b*d^2*x^2+a*d^2)^5/a^3*b^2*(d*x)^(13/2)+77/4096*d^3/(b*d^2*x^
2+a*d^2)^5/a^4*b^3*(d*x)^(17/2)+231/32768*d/a^5/b*(a/b*d^2)^(1/4)*2^(1/2)*ln((d*x+(a/b*d^2)^(1/4)*(d*x)^(1/2)*
2^(1/2)+(a/b*d^2)^(1/2))/(d*x-(a/b*d^2)^(1/4)*(d*x)^(1/2)*2^(1/2)+(a/b*d^2)^(1/2)))+231/16384*d/a^5/b*(a/b*d^2
)^(1/4)*2^(1/2)*arctan(2^(1/2)/(a/b*d^2)^(1/4)*(d*x)^(1/2)+1)+231/16384*d/a^5/b*(a/b*d^2)^(1/4)*2^(1/2)*arctan
(2^(1/2)/(a/b*d^2)^(1/4)*(d*x)^(1/2)-1)

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maxima [A]  time = 3.23, size = 392, normalized size = 1.01 \[ \frac {\frac {8 \, {\left (385 \, \left (d x\right )^{\frac {17}{2}} b^{4} d^{4} + 1760 \, \left (d x\right )^{\frac {13}{2}} a b^{3} d^{6} + 3130 \, \left (d x\right )^{\frac {9}{2}} a^{2} b^{2} d^{8} + 2648 \, \left (d x\right )^{\frac {5}{2}} a^{3} b d^{10} - 1155 \, \sqrt {d x} a^{4} d^{12}\right )}}{a^{4} b^{6} d^{10} x^{10} + 5 \, a^{5} b^{5} d^{10} x^{8} + 10 \, a^{6} b^{4} d^{10} x^{6} + 10 \, a^{7} b^{3} d^{10} x^{4} + 5 \, a^{8} b^{2} d^{10} x^{2} + a^{9} b d^{10}} + \frac {1155 \, {\left (\frac {\sqrt {2} d^{4} \log \left (\sqrt {b} d x + \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} d^{4} \log \left (\sqrt {b} d x - \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} + \frac {2 \, \sqrt {2} d^{3} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}} + \frac {2 \, \sqrt {2} d^{3} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}}\right )}}{a^{4} b}}{163840 \, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^3,x, algorithm="maxima")

[Out]

1/163840*(8*(385*(d*x)^(17/2)*b^4*d^4 + 1760*(d*x)^(13/2)*a*b^3*d^6 + 3130*(d*x)^(9/2)*a^2*b^2*d^8 + 2648*(d*x
)^(5/2)*a^3*b*d^10 - 1155*sqrt(d*x)*a^4*d^12)/(a^4*b^6*d^10*x^10 + 5*a^5*b^5*d^10*x^8 + 10*a^6*b^4*d^10*x^6 +
10*a^7*b^3*d^10*x^4 + 5*a^8*b^2*d^10*x^2 + a^9*b*d^10) + 1155*(sqrt(2)*d^4*log(sqrt(b)*d*x + sqrt(2)*(a*d^2)^(
1/4)*sqrt(d*x)*b^(1/4) + sqrt(a)*d)/((a*d^2)^(3/4)*b^(1/4)) - sqrt(2)*d^4*log(sqrt(b)*d*x - sqrt(2)*(a*d^2)^(1
/4)*sqrt(d*x)*b^(1/4) + sqrt(a)*d)/((a*d^2)^(3/4)*b^(1/4)) + 2*sqrt(2)*d^3*arctan(1/2*sqrt(2)*(sqrt(2)*(a*d^2)
^(1/4)*b^(1/4) + 2*sqrt(d*x)*sqrt(b))/sqrt(sqrt(a)*sqrt(b)*d))/(sqrt(sqrt(a)*sqrt(b)*d)*sqrt(a)) + 2*sqrt(2)*d
^3*arctan(-1/2*sqrt(2)*(sqrt(2)*(a*d^2)^(1/4)*b^(1/4) - 2*sqrt(d*x)*sqrt(b))/sqrt(sqrt(a)*sqrt(b)*d))/(sqrt(sq
rt(a)*sqrt(b)*d)*sqrt(a)))/(a^4*b))/d

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mupad [B]  time = 0.13, size = 209, normalized size = 0.54 \[ \frac {\frac {331\,d^9\,{\left (d\,x\right )}^{5/2}}{2560\,a}-\frac {231\,d^{11}\,\sqrt {d\,x}}{4096\,b}+\frac {11\,b^2\,d^5\,{\left (d\,x\right )}^{13/2}}{128\,a^3}+\frac {77\,b^3\,d^3\,{\left (d\,x\right )}^{17/2}}{4096\,a^4}+\frac {313\,b\,d^7\,{\left (d\,x\right )}^{9/2}}{2048\,a^2}}{a^5\,d^{10}+5\,a^4\,b\,d^{10}\,x^2+10\,a^3\,b^2\,d^{10}\,x^4+10\,a^2\,b^3\,d^{10}\,x^6+5\,a\,b^4\,d^{10}\,x^8+b^5\,d^{10}\,x^{10}}-\frac {231\,d^{3/2}\,\mathrm {atan}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{8192\,{\left (-a\right )}^{19/4}\,b^{5/4}}-\frac {231\,d^{3/2}\,\mathrm {atanh}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{8192\,{\left (-a\right )}^{19/4}\,b^{5/4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x)^(3/2)/(a^2 + b^2*x^4 + 2*a*b*x^2)^3,x)

[Out]

((331*d^9*(d*x)^(5/2))/(2560*a) - (231*d^11*(d*x)^(1/2))/(4096*b) + (11*b^2*d^5*(d*x)^(13/2))/(128*a^3) + (77*
b^3*d^3*(d*x)^(17/2))/(4096*a^4) + (313*b*d^7*(d*x)^(9/2))/(2048*a^2))/(a^5*d^10 + b^5*d^10*x^10 + 5*a^4*b*d^1
0*x^2 + 5*a*b^4*d^10*x^8 + 10*a^3*b^2*d^10*x^4 + 10*a^2*b^3*d^10*x^6) - (231*d^(3/2)*atan((b^(1/4)*(d*x)^(1/2)
)/((-a)^(1/4)*d^(1/2))))/(8192*(-a)^(19/4)*b^(5/4)) - (231*d^(3/2)*atanh((b^(1/4)*(d*x)^(1/2))/((-a)^(1/4)*d^(
1/2))))/(8192*(-a)^(19/4)*b^(5/4))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (d x\right )^{\frac {3}{2}}}{\left (a + b x^{2}\right )^{6}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x)**(3/2)/(b**2*x**4+2*a*b*x**2+a**2)**3,x)

[Out]

Integral((d*x)**(3/2)/(a + b*x**2)**6, x)

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